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Dynamic Dropdown Results

Thread began 1/09/2010 4:04 am by bgw1999373018 | Last modified 1/11/2010 5:55 pm by Jason Byrnes | 2460 views | 13 replies |

bgw1999373018

Dynamic Dropdown Results

I have created a Dynamic Dropdown that works perfect, well kinda. The issue I am having is when the "insert" form is submitted (WA Data Assist) it puts the ID #'s into the database instead of the selected values that were populated from the Dynamic Dropdowns. How can I fix this?

Thanks,

Bobby

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bgw1999373018

Here are the (2) values I am having problems with:

<?php echo ((isset($_POST["VehicleModel"]))?$_POST["VehicleModel"]:""); ?>
<?php echo ((isset($_POST["VehicleStyle"]))?$_POST["VehicleStyle"]:""); ?>

I am posting the "selected values" into another table if that makes any difference, which I am assuming does.

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Jason ByrnesWebAssist

create two hidden form fields to capture the labels, then use javascvript to populate the hidden form fields with the labels on change. here is an example:

php:
<form name="form1" method="post"  action="">

  <label for="select"></label>
  <select name="select" id="select" onChange="document.form1.hiddenField.value = document.form1.select[document.form1.select.selectedIndex].text">
    <option value="1">one</option>
    <option value="2">two</option>
    <option value="3">three</option>
    <option value="4">four</option>
  </select>
  <input type="hidden" name="hiddenField" id="hiddenField">
  <label for="button"></label>
  <br>
  <input type="submit" name="button" id="button" value="Submit">
  <br>
  List value = <?php echo((isset($_POST["select"]))?$_POST["select"]:""?>
  <br>
  Hidden Field Value=<?php echo((isset($_POST["hiddenField"]))?$_POST["hiddenField"]:""?>
</form>
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bgw1999373018

Originally Said By: Jason Byrnes
  create two hidden form fields to capture the labels, then use javascvript to populate the hidden form fields with the labels on change. here is an example:

php:
<form name="form1" method="post"  action="">

  <label for="select"></label>
  <select name="select" id="select" onChange="document.form1.hiddenField.value = document.form1.select[document.form1.select.selectedIndex].text">
    <option value="1">one</option>
    <option value="2">two</option>
    <option value="3">three</option>
    <option value="4">four</option>
  </select>
  <input type="hidden" name="hiddenField" id="hiddenField">
  <label for="button"></label>
  <br>
  <input type="submit" name="button" id="button" value="Submit">
  <br>
  List value = <?php echo((isset($_POST["select"]))?$_POST["select"]:""?>
  <br>
  Hidden Field Value=<?php echo((isset($_POST["hiddenField"]))?$_POST["hiddenField"]:""?>
</form>
  


I apologize Jason, but I am a little lost here. I am assuming I should NOT create a new form and just take the code above, minus the form tags, and insert it into my current form on the INSERT page? Am I going in the right direction here? Please, if possible, provide a little more detal. Thanks.

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bgw1999373018

Attached is the code from my insert.php page.

Attached Files
insertpagecode.zip
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Jason ByrnesWebAssist

No, my code was merely to demonstrate the javascript code needed.


lets take the VehicleModel select list as an example:

php:
<select name="VehicleModel" size="1" id="VehicleModel" onchange="WA_FilterAndPopulateSubList(rsVehicleStyle_WAJA,MM_findObj('VehicleModel'),MM_findObj('VehicleStyle'),1,0,false,': ')">




inside the form create another hidden form element named "VehicleModelname"

html:
<input type="hidden" name="VehicleModelname" id="VehicleModelname">




and change the select list tag to:

php:
<select name="VehicleModel" size="1" id="VehicleModel" onchange="WA_FilterAndPopulateSubList(rsVehicleStyle_WAJA,MM_findObj('VehicleModel'),MM_findObj('VehicleStyle'),1,0,false,': ');document.WADAInsertForm.VehicleModelname.value = document.WADAInsertForm.VehicleModel[document.WADAInsertForm.VehicleModel.selectedIndex].text">
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bgw1999373018

Thanks for the quick reply. I just attempted to do this and did not work. Any other ideas?

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Jason ByrnesWebAssist

please post a link.

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bgw1999373018

insert.php

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Jason ByrnesWebAssist

The script is updating the hidden form element. have you updated the insert record behavior to use the hidden form element value instead of the select list?

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