Check New User Issue

Getting PARSE syntax error when attempting to use the "Check New User"created with WebAssist
Issue is with the syntax of attempting to send the form variable "capid" in the URL call string to the "if found" webpage.

have the same in use but the pass variable is a session variable,,,, for this application i want to just pass the form variable
Can you please check my syntax

Error text is:
Parse error: syntax error, unexpected '"', expecting '-' or identifier (T_STRING) or variable (T_VARIABLE) or number (T_NUM_STRING) in /home/riclau7/member.lawg.cap.gov/Reg_Acad_Public/AcadRegAdd.php on line 12

Full php file is attached for reference

This line didn't get encoded properly.

This:
$FailedRedirect = "DuplicReg.php?capid=<?php echo((isset($_POST["capid"]))?$_POST["capid"]:"") ?>";

Should be:
$FailedRedirect = "DuplicReg.php?capid=".((isset($_POST["capid"]))?$_POST["capid"]:"") ."";

Ray - thanks and yes that worked for all of the instances that had the problem
but question ----
that coding issue was put in by the WebAssist module (not hand coded)
Does the module need to be fixed for on-going use??

Here is want a fresh php file coded using the "MySQLi Check New User" option shows for that line item

$FailedRedirect = "file:///D|/_RLdata/CAP_lawgMbr/Reg_Acad_Public/DuplicReg.php?capid=<?php echo((isset($_POST["test"]))?$_POST["test"]:"") ?>";

it threw in the "php echo" item

Yes. I've already updated the extension. If you reinstall this issue should be resolved.