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How to show jpg images in repeated region (image data stored in directory)

Thread began 2/03/2010 10:40 pm by rikaG_510 | Last modified 2/05/2010 12:13 am by rikaG_510 | 1908 views | 2 replies |


How to show jpg images in repeated region (image data stored in directory)

In my MySQL database, I have

product (table)
-productImages (filename.jpg)

I read a threads that storing images in database is not the best way, so I kept jpg files in my directory (rowing_image/shop/riggers).

I saw some thread talking about the similar topic;


I'm going to make a back end page first using DataAssist, still I reckon it's good to know this since I'm a beginner in PHP.
I need someone to help me with coding to call images along with product info.

I've tried to do it my own;
<?php header('Content-type: image/jpeg'); readfile('rowing_image/shop/riggers');?>
but then I don't know how to make this match this with each filenames...

So here is the repeated region;

<?php do { ?>
<td><?php echo $row_PRDrigger_riggers['ProductImage']; ?>
<td><?php echo $row_PRDrigger_riggers['ProductName']; ?><br />
<?php echo $row_PRDrigger_riggers['ProductDiscription']; ?><br />
<?php echo $row_PRDrigger_riggers['ProductPrice']; ?> RMB<br /></td>
<?php } while ($row_PRDrigger_riggers = mysql_fetch_assoc($PRDrigger_riggers)); ?>


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CraigRBeta Tester

you are correct that images should not be stored in a database.

the database should show the image name (and perhaps the path too).

if your existing code displays the image name held in the recordset correctly, then you're nearly there.

in Dreamweaver, choose Insert -> Image
From the pop-up, choose data sources as your image source.
Expand the recordset and choose the field where your image name is stored.

if you have the path and filename stored in the database, that should be all you need to do.

if you dont have the path stored with the image name, you need to append this to the beginning of the string.

eg if the value in your field is imagename.jpg, and it is held in the images folder, your code will look something like this...

<img src="images/<?php echo $row_PRDrigger_riggers['ProductImage']; ?>" alt="<?php echo $row_PRDrigger_riggers['ProductName']; ?>" />

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Ohhh, it worked!
It's simpler than I thought...

Thanks a lot, CraigR.

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