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SQL Query

Thread began 2/03/2010 5:20 am by johnlenehan398025 | Last modified 2/05/2010 12:36 pm by Jason Byrnes | 1103 views | 3 replies |

johnlenehan398025

SQL Query

Hi

I realise this forum is for supporting dynamic charts, but I have an Dreamweaver/ASP/SQL/ACCESS question.

I have a chart created and it is working perfectly using this SQL statement:

SELECT creator AS XLABEL, COUNT(lessontitle) AS YVALUE FROM lomaster GROUP BY creator

I am trying to modify the "COUNT(lessontitle)" part of the statement to read
"COUNT(DISTINCT lessontitle)" however this is not supported in ACCESS.

I have read that sub querys are a way to get around this, so I tried this:
SELECT creator AS XLABEL, COUNT(lessontitle) AS YVALUE FROM (SELECT DISTINCT lessontitle FROM lomaster) GROUP BY creator

I got an error back stating that "Too few paramenters were expected". Has anyone has to deal with gettign around the "COUNT(DISTINCT lessontitle)" limitation of ACCESS and have they any advice of writing sub queries or links to good tutorials if that is the way to go.

Any help is appreciated.

Thanks

J

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Jason ByrnesWebAssist

Your subquery needs to return all of the columns needed for the main query.


The main query returns the creator and lessontitle columns. your subquery is only returning the lessontitle column, since the subquery is the dataset that the main query is pulling from, it is generating the error because the creator column does not exist.


When returning more than column, the GROUP BY command is ussed to create distinct results. Try using the following query:
SELECT creator AS XLABEL, COUNT(lessontitle) AS YVALUE FROM (SELECT creator, lessontitle FROM lomaster GROUP BY lessontitle) GROUP BY creator

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johnlenehan398025

Worked it out another way!

Thanks for your help with that problem.

I kept getting an error with the code you suggested so a I tried another million combinations. And at last, one came out good!

SELECT creator AS XLABEL, COUNT(lessontitle) AS YVALUE FROM (SELECT DISTINCT creator, lessontitle FROM lomaster) GROUP BY creator

I'm not really sure how it works. I hope to get some procedural tact in SQL.

Thank you for looking at it for me.

Cheers

J

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Jason ByrnesWebAssist

OK, Glad to hear you got it working.

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