How to display images in php?

How to display images in php?

for example this picture:

attachment.php?attachmentid=1067&d=1257034004


thanks!

Not sure I understand your question.

The image tag (which is HTML) is used to display images. So in your code you would have something like: <img src="images/myimage.jphg" />.

If you wanted to generate the image dynamically, say with an image name stored in your database, you could use PHP to create the recordset and then populate the file name - similar to this: <img src="images/<?php echo $recordset_row['image']; ?>" />

Not sure what else to add... maybe you can provide more specific goals for what you are trying to accomplish.

thanks!


I want to show the image as a url to protect it, for example:

Instead of showing <img src="http://www.website.com/image/image.jpg" width="229" height="152" />

I want to show the image url
image.php?id=1542

If you do not actually want to display an image but just a link to it you can do the same as above but just use the anchor tag for a hyperlink like this:

<a href="yourimage path here">your image path here</a>

Probably not what you are after, but if you wanted to create a download link to an image (or other file) that completely hides the path to those files, there is a good script (one page) at download.php

This is particularly useful for digital downloads.

Originally Said By: arteydiseno381654

  thanks!


I want to show the image as a url to protect it, for example:

Instead of showing <img src="http://www.website.com/image/image.jpg" width="229" height="152" />

I want to show the image url
image.php?id=1542  

Take a look at these PHP functions to make a php script that reads and outputs and image:

imagecreatefromjpeg()
function.imagecreatefromjpeg.php

imagejpeg()
function.imagejpeg.php

Your PHP page would essentially read in the existing JPG file, then would output it from the PHP script. Something like this would work:

$im = imagecreatefromjpeg('image.jpg');
header('Content-type: image/jpeg');
imagejpeg($im);
imagedestroy($im);

This assumes image.jpg is in the same directory as the PHP script, but really it could be anywhere and you can just adjust that path accordingly. You can also do some cool things like check to make sure the image is being requested from your server (to prevent outside sites from linking to it directly), add watermarks, etc from within this PHP script.

-justin

I have found that if you put the image as a background url image in a div using CSS then you cannot right-click to download the image or show image in new tab. You would need to add the CSS code in the page header (as php will not work in the external style sheet)



Hope this helps
Vanrooj

you can also do it in flash as an swf

--- My baby:

You can use Digital File Pro and the Download File server behavior. Then use that page as the image source... passing in a url parameter to specify the image or imageID if you store the image locations in a database.