inserting info in record along with image

in a previous thread, i learned to use DataAssist insert single record to insert Client File Name from the DFP behavior.

I want to know if i can insert additional information to the db record in order to get the path correct to the image from DFP image upload

ie, the image file from DFP goes to images folder and the file name is filename.jpg.
Using the DataAssist insert single record and Client File Name, it inserts 'filename.jpg'

I want it to insert 'images/filename_lg.jpg'

code is ........$WA_DFP_UploadStatus["WA_UploadResult1"]["clientFileName"].......

i tried .$WA_DFP_UploadStatus["WA_UploadResult1"]["images/clientFileName_lg"]

nothing inserted

thanks for your help,
Jim Balthrop

Jim,

You're on the right track - but you need to concatenate before the Upload File Name's variable.

This whole string ($WA_DFP_UploadStatus["WA_UploadResult1"]["clientFileName"]) results in the variable just for the file name.

In your update statement, it will look like this:
"".$WA_DFP_UploadStatus["WA_UploadResult1"]["clientFileName"] .""

The tool automatically concatenates empty strings before and after to ensure that only the variable passes.

So to change the database data to add the file's folder in the column, you will need to concatenate like this:

"".'/images/'. $WA_DFP_UploadStatus["WA_UploadResult1"]["clientFileName"] .""

Notice a couple of things - I used single quotes to tell PHP to interpret the string as actual text. The other thing I did which you may want to change is that I added a forward slash before images to make it a root relative path rather than a page relative path. That way if you just echoed the data result somewhere later on any page of the site - regardless of folder hierarchy - the path would still be correct. If you want to keep it so the folder was still page relative, just remove that forward slash in the front.

Cheers,

Brian

thanks Brian

that works just like i wanted except that for image 2 upload i resized the same image to a larger size so with the DFP upload i used

'FileName' => "[FileName]_lg",

named the image file filename_lg.jpg

so i had to change ["clientFileName"] to ["serverFileName"] for the insert data

thanks for your help