MySQLi recordset not returning correct values

I have a search form on one page, and the results on another page.

This is my form:
<form action="ocodeSearch.php" method="post">
Search by OCODE <input name="ocode" type="text" id="ocode" size="15">
<input name="submit" type="submit" id="submit" value="Search">
</form>

This is the query on the results page:
<?php require_once('Connections/nelson.php'); ?>
<?php require_once('webassist/mysqli/rsobj.php'); ?>
<?php
$strQuery = new WA_MySQLi_RS("strQuery",$nelson,1);
$strQuery->setQuery("SELECT * FROM nelsonoc WHERE ocode LIKE ?");
$strQuery->bindParam("s", "".(isset($_POST['ocode'])?$_POST['ocode']:"") ."", "-1"); //colname
$strQuery->execute();?>

<p>Total records: <?php echo $strQuery->TotalRows ?> </p> No matter what I enter in the search field, it always returns a record count of 0. I'm also getting an error when I create the recordset (see screen print).

ocode is a varchar field. Please see attached screen prints. Hopefully, you can tell me why it's not working.

Thank you.

The code looks correct. Is there any way I could get FTP access and a URL to reproduce? What are you entering into the search field?

I'll have to debug this one live to see what is going on.

Unfortunately, it's localhost only right now. The real site is live,but i can't alter it. It's a very old application, and I'm trying to give them a couple of extra features.

Can you attach the page? That might be enough... It could be an issue with your local connection or database. Maybe try creating a new page with a different name you can test live with to see if it is an issue with the localhost.

I did test the DB and code, because I tried connecting it manually, and it worked. I will attach the pages.

I'll have to set up screen sharing to debug this with you. I don't see anything wrong with the code on the page and if it is only available on localhost, then I'll need to screen share to see and debug it properly.

I probably won't have time until later this week. I'll let you know, okay? Thanks.