Dynamic dropdown insert to database

I've done the Dynamic Dropdowns tutorial with Data Bridge 2.0 (http://www.webassist.com/tutorials/Dynamic-Dropdowns-with-Data-Bridge-2-0#last_comment). The question that unfortunately is not explained - is how to save the selections from both select-lists, to another table?

If I want both Towns and Teams selections to be saved in a new table - how to do this?
Since, among other things, there is already a form on the page that processes the choice from Town, you can't create a submit button, or am I thinking wrong?

I would rather see this explained in the same tutorial - as it should be of general interest.

As long as the select lists are inside the same <form> tag, they will both be submitted with the form and can be used for insert just like any other form element.

Okay! But how do I do with the ID question? I want to save the respective value from ID, not TownName and teamName. How do I change the select-list options?

You should be able to set the value of the select list options to the ID and use that for the insert. I'm afraid I might be missing the question, but whatever you want saved to the database should be the value of the select list.

I don't understand how to change the querys, and how to change select-lists to display id instead. According to the tutorial, both value and label = teamName, on the childSelect page and townName on the main page. Value should be ID instead I think. But this does not work. Then childSelect will not be displayed. Please explain how this will work. Both childSelect page and main.

The select value should be the ID and then the recordset on the child list plugin should filter based on the ID.

On which page should select value be ID, both pages?
What should the recordset on the child list look like?
Here's how it is now:
<?php
$rsTeams = new WA_MySQLi_RS("rsTeams",$dynamicDropdown,0);
$rsTeams->setQuery("SELECT * FROM teams WHERE teamTown = ? ORDER BY teamName ASC");
$rsTeams->bindParam("s", "".(isset($_POST['towns'])?$_POST['towns']:"") ."", "-1"); //colname
$rsTeams->execute();
?>
Thanks in advance!

The select lists value should be what you want inserted to the database for both lists.

Just change the column in the WHERE clause to match the value from the select list submitted.

I have tried the following, but the contents of child select list are not displayed.

The child select should be:

SELECT * FROM teams WHERE town_id = ?

not

SELECT * FROM teams WHERE teams_id = ?