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complex server validation

Thread began 3/02/2020 8:16 am by SCar87011738 | Last modified 3/03/2020 9:48 am by Ray Borduin | 71 views | 4 replies |

SCar87011738

complex server validation

Hello all,
I have a complex form with a select.
If the user select a specific select option, another two fields (Field1 and Field2) are displayed (I use Jquery to handle hidden divs).
So, I need to validate the additional fields only if they are displayed.
And if they are displayed I should check if the user enters the correct values in both fields.
Example: if Field1 is < 100 and Field2 is < 200 validation should fail and an error message should be displayed.

I'm currently using this server variable but it's not working:

Validation type: number (international, min: 0; max: empty; decimals: 0)
Validation server:
(((isset($_POST["myselect"]) && $_POST["myselect"] == "8") && ($_POST["field1"] <100 && $_POST["field2"] <200))?$_POST["field1"]:"-1")

How can I intercept this error?

TIA
tony

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Ray BorduinWebAssist

You could probably use server validation and do a number validation on that value to test if it is greater than zero.

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SCar87011738

Thanks Ray,
I have already used server validation but I can't find the right formula in the server variable field:

Validation type: number (international, min: 0; max: empty; decimals: 0)
Validation server:
(((isset($_POST["myselect"]) && $_POST["myselect"] == "8") && ($_POST["field1"] <100 && $_POST["field2"] <200))?$_POST["field1"]:"-1")



This simple doesn't work.
Perhaps I am missing something in the syntax (parenthesis).

Do this should work?
TIA
Tony

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SCar87011738

Hello all,
perhaps I solved it:
This is the syntax that seems to work:

((isset($_POST["myselect"]) && $_POST["myselect"] == "8" && $_POST["field1"] < "100" && $_POST["field2"] < "120" )?"-1":"0")



Please note I used server validation as NUMBER (minimum: 0).

Do you see something wrong here?
Is there something better for it?

TIA
tony

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Ray BorduinWebAssist

It looks like that would work to me.

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