Multiple Conditions in If Clause Question

Is it possible to have several options in an if clause?

If possible, I would like to combine these two conditions into one statement so that I would get either result A or B and, if neither condition was met, then get the (else) default condition would be returned.

Condition 1:

<?php
if ($rsAgenda->getColumnVal("address_type") == "A")
{include("agenda_menu_2.php");
}
else
include("agenda_menu.php");
}
?>

Condition 2:

<?php
if ($rsAgenda->getColumnVal("address_type") == "B")
{include("agenda_menu_3.php");
}
else {
include("agenda_menu.php");
}
?>

That works!


Many thanks again for your help.

I have a situation where I have a video file and and image file in the database. All records have an image file but only some have a video file.
I also have a 'show_vid' field.

When this is set to "Y", I only want to only show the video file, otherwise when it is checked "N" it should show the image instead.

This works when there is not a video, but when there is a video, and 'set_id' is set to "Y", I get BOTH the video file and the image file.

Obviously, I am missing something in my syntax below:
---------------------------

<?php
if ($rsObservation->getColumnVal('show_vid') == "Y")
{echo $rsObservation->getColumnVal("video",false);
}
else
{echo'<img src="upload/news/';
echo $rsObservation->getColumnVal("image",false);
echo '" width="1920" height="1080" alt=""/>';
}
?>
----------------------

UPDATE: Actually this now seems to work like this using two PHP statements:

---------------------------

<?php
if ($rsObservation->getColumnVal('show_vid') == "Y")
{echo $rsObservation->getColumnVal("video",false);
}
else {
echo "";}

?>

<?php
if ($rsObservation->getColumnVal('show_vid') == "N")
{echo'<img src="upload/news/';
echo $rsObservation->getColumnVal("image",false);
echo '" alt=""/>';
}
else {
echo "";}

?>
----------------------------------------------------

Thanks for any advice.