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Basic Search Form

Thread began 7/21/2014 12:43 am by Jason | Last modified 8/28/2014 10:46 am by Jason | 2644 views | 101 replies |

Jason

Ridiculously complex search Form

Can someone please help me figure out what I did wrong in this code? I'm trying to type a first and last name into the 2 search boxes and then have it output the results that match $ServingQuery. Right now nothing happens though.



<?php require_once('Connections/local_i.php'); ?>
<?php require_once('webassist/mysqli/rsobj.php'); ?>
<?php
$UserFirstName = new WA_MySQLi_RS("UserFirstName",$local_i,0);
$UserFirstName->setQuery("SELECT pcms2_users.UserID, pcms2_users.UserFirstName FROM pcms2_users");
$UserFirstName->execute();
?>
<?php
$UserLastName = new WA_MySQLi_RS("UserLastName",$local_i,0);
$UserLastName->setQuery("SELECT pcms2_users.UserID, pcms2_users.UserLastName FROM pcms2_users");
$UserLastName->execute();
?>
<?php
$ServingQuery = new WA_MySQLi_RS("ServingQuery",$local_i,1);
$ServingQuery->setQuery("SELECT pcms2_users.UserID, pcms2_users.UserFirstName, pcms2_users.UserLastName, kids_program_shifts.kp_team_id, kids_program_shifts.kp_volunteer, cleaning_team_shifts.cleaning_team_id, cleaning_team_shifts.ct_volunteer, serving_team.* FROM pcms2_users INNER JOIN kids_program_shifts ON pcms2_users.UserID = kids_program_shifts.kp_volunteer INNER JOIN cleaning_team_shifts ON pcms2_users.UserID = cleaning_team_shifts.ct_volunteer INNER JOIN serving_team ON cleaning_team_shifts.cleaning_team_id = serving_team.id AND kids_program_shifts.kp_team_id = serving_team.id");
$ServingQuery->execute();
?>
<!doctype html>
<html>
<head>
<meta charset="utf-8">
<title>Untitled Document</title>
</head>

<body>
<form method="get">
<input type="search" name="UserFirstName" id="UserFirstName">
<input type="search" name="UserLastName" id="UserLastName">
<input type="submit" name="search" value="search">
<?php
while(!$ServingQuery->atEnd()) {
?>
<?php echo($ServingQuery->getColumnVal("UserFirstName")); ?>
<?php echo($ServingQuery->getColumnVal("UserLastName")); ?>
<?php echo($ServingQuery->getColumnVal("team")); ?>
<?php
$ServingQuery->moveNext();
}
$ServingQuery->moveFirst(); //return RS to first record
?>
</form>
</body>
</html>

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Jason ByrnesWebAssist

1) You don't need 3 recordsets, only 1

2) In the recordset you need to add a where clause to filter the first and last name columns on the entered values

WHERE UserFirstName = paramFirstName OR UserLastName = paramLastName

then in the variables section create 2 new variables as:
name: paramFirstName
type: Text
default Value: -1
Runtime value: <?php echo(isset($_GET['UserFirstName'])?$_GET['UserFirstName'];""); ?>

name: paramLastName
type: Text
default Value: -1
Runtime value: <?php echo(isset($_GET['UserLastName'])?$_GET['UserLastName'];""); ?>

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Jason

Followed your instructions. When I try to test that page now I get this error:
Parse error: syntax error, unexpected ';' in C:\xampp\htdocs\serving\Untitled-2.php on line 16

And this is line 16:
$ServingQuery->bindParam("s", "".(isset($_GET['UserFirstName'])?$_GET['UserFirstName'];"") ."", "-1"); //paramFirstName

Here's the rest of the page after making the changes in case you need to see it.

<?php require_once('Connections/local_i.php'); ?>
<?php require_once('webassist/mysqli/rsobj.php'); ?>
<?php
$ServingQuery = new WA_MySQLi_RS("ServingQuery",$local_i,1);
$ServingQuery->setQuery("SELECT pcms2_users.UserID, pcms2_users.UserFirstName, pcms2_users.UserLastName, kids_program_shifts.kp_team_id, kids_program_shifts.kp_volunteer, cleaning_team_shifts.cleaning_team_id, cleaning_team_shifts.ct_volunteer, serving_team.* FROM pcms2_users INNER JOIN kids_program_shifts ON pcms2_users.UserID = kids_program_shifts.kp_volunteer INNER JOIN cleaning_team_shifts ON pcms2_users.UserID = cleaning_team_shifts.ct_volunteer INNER JOIN serving_team ON cleaning_team_shifts.cleaning_team_id = serving_team.id AND kids_program_shifts.kp_team_id = serving_team.id WHERE pcms2_users.UserFirstName = ? AND pcms2_users.UserLastName = ?");
$ServingQuery->bindParam("s", "".(isset($_GET['UserFirstName'])?$_GET['UserFirstName'];"") ."", "-1"); //paramFirstName
$ServingQuery->bindParam("s", "".(isset($_GET['UserLastName'])?$_GET['UserLastName'];"") ."", "-1"); //paramLastName
$ServingQuery->execute();
?>
<!doctype html>
<html>
<head>
<meta charset="utf-8">
<title>Untitled Document</title>
</head>

<body>
<form method="get">
<input type="search" name="UserFirstName" id="UserFirstName">
<input type="search" name="UserLastName" id="UserLastName">
<input type="submit" name="search" value="search">
<?php
while(!$ServingQuery->atEnd()) {
?>
<?php echo($ServingQuery->getColumnVal("UserFirstName")); ?>
<?php echo($ServingQuery->getColumnVal("UserLastName")); ?>
<?php echo($ServingQuery->getColumnVal("team")); ?>
<?php
$ServingQuery->moveNext();
}
$ServingQuery->moveFirst(); //return RS to first record
?>
</form>
</body>
</html>

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Jason ByrnesWebAssist

My apologies, I Had a syntax error for the run time values in the parameters, they should be:


name: paramFirstName
Runtime value: <?php echo(isset($_GET['UserFirstName'])?$_GET['UserFirstName']:""); ?>

name: paramLastName
Runtime value: <?php echo(isset($_GET['UserLastName'])?$_GET['UserLastName']:""); ?>

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Jason

That may or may not have worked. The search fields and button display correctly now, but I'm not getting any results. When I test the query it says no data. I'm guessing that means I made a mistake in my query?

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Jason ByrnesWebAssist

I'll need to troubleshoot directly, see the private message section.

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Jason

See private message

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Jason

See private message.

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Jason ByrnesWebAssist

your query was set to use a inner join on 3 other tables, those tables did not have any related records, so the query was not retunring any records, even without the where clause.

i changed the inner join to left join

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Jason

We're getting closer, but not quite what I was going for. I'll detail it out a little better in the private message section.

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