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Retaining state on update of date picker and a select

Thread began 5/13/2013 11:57 am by superpac250441 | Last modified 5/16/2013 9:46 am by Jason Byrnes | 478 views | 3 replies |

superpac250441

Retaining state on update of date picker and a select

Hi there,
1) I have this select box on an update form. Can someone tell me how to retain the previous values:

<select class="formMenufield_Medium" name="NewsCategory" id="NewsCategory" tabindex="1">
<option value="">Please select</option>
<?php
do {
?>
<option value="<?php echo $row_rsNewsCat['CategoryName']?>"><?php echo $row_rsNewsCat['CategoryName']?></option>
<?php
} while ($row_rsNewsCat = mysql_fetch_assoc($rsNewsCat));
$rows = mysql_num_rows($rsNewsCat);
if($rows > 0) {
mysql_data_seek($rsNewsCat, 0);
$row_rsNewsCat = mysql_fetch_assoc($rsNewsCat);
}
?>
</select>


2) I have a date picker and I am hoping to retain value here on the previously selected date:

<input id="Date" name="Date" type="text" value="<?php echo((isset($_GET["invalid"])?ValidatedField("newsarticlesupdate","Date"):"".(($row_WADAnewsarticles["Date"])?date("n/d/Y",strtotime($row_WADAnewsarticles["Date"])):"")."")); ?>" class="formTextfield_Medium" tabindex="5" onblur="hideServerError('Date_ServerError');" />

Many thanks

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Jason ByrnesWebAssist

For the Select List, click the list in design View.

in the property inspector, click the dynamic button, for the Slect Value Equal to ioption, click the lightning bolt icon and selct the coresponding column from the WADAnewsarticles recordset.

for the date, it is already coded to return the previously inserted date.

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superpac250441

Many thanks Jason. That sorted out the drop downs perfectly.

The datepicker has been more problematic. I set it to yyyy-mm-dd and got it running okay when I added the following code at line1:

<?php
if(isset($_POST['date'])) {
$_POST['date'] = date("Y-m-d", strtotime($_POST['date']));
}
?>

So on the front end page it posts eg. 2013-05-15 00:00:00

If I just want date and not time, do I change the code to:

<?php
if(isset($_POST['date'])) {
$_POST['date'] = date("Y-m-d");
}
?>

Many thanks Jason

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Jason ByrnesWebAssist

Because the field is a date time field, the time is required.

you can leave it off when displaying the date on the results page by using the y-m-d date format:

<?php echo(date("Y-m-d", strtotime($row_recordsetName['date']))); ?>

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