how do i evenly display a repeating content across full width of a website?

Hello, I have always wondered this....

Lets say I have 3 columns of even length (eg 200px width) and lets say my website is 940px width obviously the 3 columns would have and extra 40px left...however I would like a 20px gap between the columns..if I use inline css I could simply put a margin-right:20px on the first and second column..perfect....until....i want to turn the content into database driven content using a repeat region...now how can I do the same using a repeat region because if I just create a column of 200px width with a 20px margin-right then the third column would drop to next row since the columns+the margins would equal 960 and my website width is 940px. So basically I need to tell the repeat region that on every 3rd record in the database not to use a apply a margin-right:20px so only the 1st and 2nd records in the database would use this inline css.

Chris

Usually you would just make your page 960px wide and give everything a 20px margin right.

If you want to do it the way you are trying, you would have to add a little hand coding to treat every third column differently.

This would be done by adding a counter to keep track of the number of divs like:

<?php
$row_count=1;
?>

right above the DO loop line for your repeat region.

Then in the line right above the WHILE line that ends your loop you would add:

<?php
$row_count++;
?>

Then you can add code that would only appear every third row like:

<?php echo(($row_count%3==0)?' style="margin-right=0;"':' style="margin-right:20px"'); ?>

Thanks Ray, with the code you provided how would I integrate the image I want to span accross the repeat, ie <img src="logos/<?php echo $row_suppliers['SuppliersLogo']; ?>" alt="" width="211" height="53">


<?php
$row_count=1;
?>
<?php do { ?>
<?php echo(($row_count%3==0)?' style="margin-right=0;"':' style="margin-right:20px"'); ?>
<?php
$row_count++;
?>
<?php } while ($row_suppliers = mysql_fetch_assoc($suppliers)); ?>


Cheers

Chris

All sorted..yet agian thanks Ray :) excellent method :)
Chris