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single item discount by coupon code

Thread began 5/19/2011 8:59 am by sam308940 | Last modified 5/20/2011 4:35 pm by Jason Byrnes | 905 views | 5 replies |

sam308940

single item discount by coupon code

my client wants to give a particular item a discount, but based on coupon code. how can i do a single item discount like this? i just need to be pointed in the right direction...........

i have done a gazillion codes that give free shipping, % off, flat rate off etc. but nothing ever for a single item.

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Jason ByrnesWebAssist

you will need to know the ID of the item to apply the discount code to.
In addition to the Based on session value trigger that is used for coupon codes, add another trigger:
Presence of an Item In the cart:
If item "<item ID>" "exists" in the cart.


the add you flat rate discount.

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sam308940

Hi - wow you are fast today!

i did kind of figure things out. but i have an issue with it.

lets say someone adds the item we want on sale, in a size 6 and a size 10. it shows up as 2 items separately in the cart.

when it calculates the discount total, it only calculates for 1 of them, not both. so - i need to add qty to the calculation. how do i grab the total quantity of that item in the cart. (not the qty of total items in cart)

Here is my code so far.....
//eCart Rule
function WAEC_JULES_LUCKY6() {
$totalDiscount = 0;
if (true && ((sizeof($this->Items) > 0) && ($this->InCart("SS2411") == true)) && (((isset($_SESSION['discount_code'])?$_SESSION['discount_code']:"") == "LUCKY6") OR ((isset($_SESSION['discount_code'])?$_SESSION['discount_code']:"") == "lucky6"))) {
$totalDiscount += (floatval($this->GetInfo("SS2411", "TotalPrice")) * .3);//Result
}
return WA_eCart_FormatNumber($totalDiscount, $this->ForceDecimalsC, $this->DecimalPlacesC);
}
//eCart Rule

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Jason ByrnesWebAssist

Instead of using "Items column value" in the calculation section, use "Based on items with a specific value":
Total Of "TotalPrice" where "ID" has a value of "SS2411" "Times" "0.3"

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sam308940

ok that solved it. thanks.

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Jason ByrnesWebAssist

you're welcome.

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