Show If

I am having trouble figuring out Show If in PHP

If a field in a Recordset has a value, I want to display a table on my page with the content in it.

Here is what I have, but it doesn't work.

<?php if (!empty($row_news['celebrating']))?>
<?php do { ?>
<table width="280" border="0" cellpadding="8" cellspacing="0" class="announcetable">
<tr>
<td align="left" valign="top" bgcolor="#EEE8DB" class="bodytext"><?php echo $row_news['celebrating']; ?></td>
</tr>
</table>
<?php } // end if ?>

Easy enough to do in ASP, but I don't know the syntax in php.

Any help would be appreciated.

Looks like you are missing a few things. On the "if" line, you need a "{" before the ?>. It also looks like you you have a "do {" line, but no while condition that goes with that. So I think you can remove the do line as well. That should get it working.

Thank you very much.
That was exactly the problem!