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Difficulties getting my images to display

Thread began 1/25/2011 9:22 pm by Mike Russavage | Last modified 1/27/2011 9:55 pm by Mike Russavage | 1441 views | 2 replies |

Mike Russavage

Difficulties getting my images to display


I am having difficulties getting my images to display.

I am passing a url variable to my display page

My display page catches the url variable (using the code below)

However does not display image.

Any assistance in the correct coding would be greatly appreciated

<?php require_once('Connections/bari.php'); ?>
if (!function_exists("GetSQLValueString")) {
function GetSQLValueString($theValue, $theType, $theDefinedValue = "", $theNotDefinedValue = "")
if (PHP_VERSION < 6) {
$theValue = get_magic_quotes_gpc() ? stripslashes($theValue) : $theValue;

$theValue = function_exists("mysql_real_escape_string") ? mysql_real_escape_string($theValue) : mysql_escape_string($theValue);

switch ($theType) {
case "text":
$theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL";
case "long":
case "int":
$theValue = ($theValue != "") ? intval($theValue) : "NULL";
case "double":
$theValue = ($theValue != "") ? doubleval($theValue) : "NULL";
case "date":
$theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL";
case "defined":
$theValue = ($theValue != "") ? $theDefinedValue : $theNotDefinedValue;
return $theValue;
$colname_Recordset2 = "-1";
if (isset($_GET['PIC'])) {
$colname_Recordset2 = $_GET['PIC'];
mysql_select_db($database_bari, $bari);
$query_Recordset2 = sprintf("SELECT * FROM xcart_images_p WHERE imageid = %s ORDER BY imageid ASC", GetSQLValueString($colname_Recordset2, "int"));
$Recordset2 = mysql_query($query_Recordset2, $bari) or die(mysql_error());
$row_Recordset2 = mysql_fetch_assoc($Recordset2);
$totalRows_Recordset2 = mysql_num_rows($Recordset2);

Should display here - however no image appears.

<div id="sideleftLgProductPic"><img src="<?php echo $row_Recordset2['image']; ?>" width="395" height="326" /></div>


Mike Russavage

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DarylBeta Tester

are your images stored in the same directory as your page?

If not you would need to add your folder location before the image file name eg.

<div id="sideleftLgProductPic"><img src="../images/<?php echo $row_Recordset2['image']; ?>" width="395" height="326" /></div>
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Mike Russavage

Images still not displaying

Hello Daryl,

First and foremost, thank you for your reply and assistance/recommendation.

I have tried every combination of the directory to prefix the directory location as you suggested.

However no luck in generating the image.

The site is under construction with temporary link redirects I am rebuilding the site and database on a remote server tonight. (hoping this eliminates confusion in pointing to the directory location of the images)

I will try again to prefix correctly to generate image. Still no luck

I finally changed the recordset field from the image (BLOB) to the filename and the image displayed.

once again thanks


Mike Russavage

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