Validation Conundrum
I am attempting server validation on a simple form (registration.php) that posts to thank_you.php. The items needed to server validate are only email and user name.
It seems logical that you must have a pair of items to validate against each other - a local form value and a value existing in a corresponding field on the database. But in my case, I do not get the option of both - only one shows up in the sequence I have carefully followed in the instructions.
As I use the tool, the session variable list presented as my first choice contains:
1) WA Cookies <?php echo((isset($_COOKIE[""]))?$_COOKIE[""]:"") ?>
email <?php echo((isset($_COOKIE["email"]))?$_COOKIE["email"]:"") ?>
password <?php echo((isset($_COOKIE["password"]))?$_COOKIE["password"]:"") ?>
remember <?php echo((isset($_COOKIE["remember"]))?$_COOKIE["remember"]:"") ?>
2) Session <?php echo $_SESSION['']; ?> or
<?php echo $_SESSION['WADbSearch1_user_Results']; ?> or
<?php echo $_SESSION['WADA_Insert_user']; ?> or
<?php echo $_SESSION['WADbSearch1_questions_Results']; ?> or
<?php echo $_SESSION['WADA_Insert_questions']; ?>
3) Cookie <?php echo $_COOKIE['']; ?> or
<?php echo $_COOKIE['email']; ?> or
<?php echo $_COOKIE['password']; ?> or
<?php echo $_COOKIE['remember']; ?>
I have chosen "like entry" validation.
But when I am asked to present the next entry ( by clicking the + sign ) in the 'choose a variable to trigger validation) all the options are exactly the same, and I am not sure what to present to validate against the first choice. (I am not even sure what the first choice should have been...)
As I said, all I want to do is validate the username and email against what is already in the database.
Can you help me out? Thanks so much!
Eddie
