really what you are asking is a very broad question. there are a few key concepts you will need to grasp to be abel to create something like this
1) Master detail page set.
a good example of this is the results and detail page created by data assist.
The idea is to have a master Page that lists all of the posible records. Lets use Users as an example, the master would show all of the users. The link to the detail page will pass the User_ID valu as a querystring. This querystring value is used to filter the recordset to return only the one record where the USER_ID column is equal to the querystring that was passed.
2) Joined Queries.
A joined query is a query that returns related information from two or more tables.for you situation, the join query will look like:
SELECT User.* Venue.* Restaurant.* Meeting.*
INNER JOIN Venue ON User.User_ID = Venue.User_ID
INNER JOIN Restaurant ON User.User_ID = Restaurant.User_ID
INNER JOIN Meeting ON User.User_ID = Meeting.User_ID
you can modify this to return a specific users Data by adding a where clause:
WHERE Users.User_ID = $_GET['User_ID']
3) SQL math commands
To return a count of records where a column is equal to yes require using a where clause and the count command on the ID column:
SELCT COUNT(id) as recCount From tabelName WHERE colName = 'yes'
you can take the SQL example I gave above and modify it to add the count and the where clause.
If there are specific steps you are struggling on, please let us know.