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How can I incorporate the show if server behavior in an existing PHP script?

Thread began 3/30/2016 2:36 am by markhaynes75235 | Last modified 4/05/2016 2:47 pm by markhaynes75235 | 314 views | 12 replies

Ray BorduinWebAssist

Did you add the validate field to the jquery form submit? I'm afraid I'm getting a little lost about where it is failing and why at this point.

You can try adding debug code to the validation... but since you are using jquery for the form submit I'm not quite clear on how the server validation is going to work.

Maybe write the values when the server validation is run to see if they have the values you would expect:


$WAFV_Errors .= WAValidateLE($_SESSION['captcha_Security_Code_1'] . "",$_POST['verify'] . "",true,1);
die($_SESSION['captcha_Security_Code_1'].":".$_POST['verify']);

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