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MySQLi Log In User - How to detect if a user is logged in and how to hide certain content based on that (not auth levels)

Thread began 10/03/2014 10:31 am by Nathon Jones Web Design | Last modified 10/03/2014 12:53 pm by Jason Byrnes | 491 views | 5 replies |

Nathon Jones Web Design

MySQLi Log In User - How to detect if a user is logged in and how to hide certain content based on that (not auth levels)

I need to display either a "Sign in" button or a "Log Off" button depending on whether or not a user is logged in or not.
Can this be done considering I've built the whole thing in MySQLi?

Thank you
NJ

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Jason ByrnesWebAssist

When you create the login behavior, the First setting on the general tab is the login name.

On login success a session variable is created using the login name as:
WA_AUTH_<login name>

so for example if you name the login "MyLogin", the session will be created as
WA_AUTH_MyLogin

you can create an if statement to check for that session variable and show logged in or not logged:

<?php
@session_start();
if(isset($_SESSION['WA_AUTH_MyLogin'])) {
?>
Logged In
<?php } else { ?>
Not Logged In
<?php } ?>
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Nathon Jones Web Design

Receiving a Parse error with that code:

Parse error: syntax error, unexpected 'if' (T_IF) in C:\inetpub\wwwroot\smt\smtadmin\navbar.php on line 27

Line 27 is:
if(isset($_SESSION['WA_AUTH_USER'])) {

Thank you.
NJ

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Jason ByrnesWebAssist

sorry, forgot the semi colon at the end of the session_start line.

that line should be:
@session_start();

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Nathon Jones Web Design

Thank you. That's fixed it.

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Jason ByrnesWebAssist

you're welcome.

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