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Insert ID not set for subsequent transaction

Thread began 6/14/2012 4:33 pm by neo314 | Last modified 6/15/2012 4:51 pm by neo314 | 479 views | 4 replies |

neo314

SOLVED: Insert ID not set for subsequent transaction

I have a gallery program in which an image can have a title and description as well. The Image's name determined by a formula, so the flow is:


  1. Insert the Title & Description
  2. Upload file and rename based on a formula which includes the Insert ID and works.
  3. Update the gallery's Icon Image ID to be the Insert ID if the icon has not been set.
  4. Update the Image record to include the new file name.


What is strange is that the Insert ID is referenced in steps 2, 3, & 4, but works in 2 & 4 correctly and inserts the last used value in step 3.


In other words, if I just inserted image 7 into gallery 3; created gallery 4 (new so no icon set yet); and add an image to gallery 4, the image has the correct Insert ID in the name and the WHERE clause for step for is correct because the file name is updated correctly, BUT gallery 4 gets 7 assigned to the icon's ID foreign key field.


The order of the code is correct, so I cannot understand what is happening here.

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Jason ByrnesWebAssist

please send files so I can examine the code. Without seeing the code, I will not be able to tell what is wrong.

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neo314

Would you mind opening a support case. I prefer not to post the file in the forum.

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Jason ByrnesWebAssist

I have created a support ticket so we can look into this issue further.

To view and edit your support ticket, please log into your support history:
supporthistory.php

If anyone else is experiencing this same issue, please append to this thread.

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neo314

Never mind. I figured it out. The trigger is allowing the tranaction on page load when it should be the previous value (duh).

Sorry for any inconvenience. Let me take this opportunity to beg for the ability to create formula triggers like IF form is posted AND this value = 0...

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