FB Share button only takes me back to index page

please see www.xf.co.za

When you use the FB Share button it only points me back to the index page.

Also very fustrating:... I was forced to use the "Hide with Share" option as WA Social kept placing the share buttons vertically underneath each other instead of next to each other. I made a seperat Div class SocialMedia (see line 177) to place the share buttons in.

Google +1 doesnt seem to be working correctly but this may not be the plugin's problem, please advise.

Warren

looking at the source of your page i see the following error:

<div class="icons"> <a name="fb_share" type="icon" href="#" onclick="window.open('http://www.facebook.com/sharer.php?u=<br />
<b>Notice</b>: Undefined index: REQUEST_URI in <b>C:\Domains\xf.co.za\wwwroot\index.php</b> on line <b>152</b>

it looks like the path for the page is set to use a system path instead of a web address, send a copy of the page so i can see the code generating the error.


when the icons are stacking vertically, it usually means that the container they are in does not have enough room, if you send a link to page where the icons are stacking vertically, i can troubleshoot that for you.

www.xf.co.za/

Its the home page... Thx alot

How do i send you a copy of the page, the forum wont let me attach a php file?

Ok I have attached the index page

compress the file into a zip archive and attach the zip file.

Here is the Zip file you requested

try adding the following code at line 1 to fi this issue:

<?php

if (!isset($_SERVER['REQUEST_URI'])){

       $_SERVER['REQUEST_URI'] = substr($_SERVER['PHP_SELF'],1 );

       if (isset($_SERVER['QUERY_STRING'])) { $_SERVER['REQUEST_URI'].='?'.$_SERVER['QUERY_STRING']; }

}

?>

Thx Jason that is working well now with FB, Thx.

Only prob is that the link is being shared as www.xf.co.zaindex instead of index .

How do I fix this. When you click on the incorrect link on FB it doesnt find any page.

Also, if Im having a similar prob on other pages can I use the same piece of code?

hmmm, change this line:
[php]
$_SERVER['REQUEST_URI'] = substr($_SERVER['PHP_SELF'],1 );
[php]


to:
[php]
$_SERVER['REQUEST_URI'] = $_SERVER['PHP_SELF'];
[php]


yes, if you run into this issue again, you can reuse the code i provided. the problem is that your server does not define the REQUEST_URI server variable, this code is used to define it manually.