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Server folder variable please

Thread began 4/02/2011 12:51 pm by Paul | Last modified 4/03/2011 3:46 am by Paul | 946 views | 2 replies |

PaulBeta Tester

Server folder variable please

I am using Digital File Pro 2 and Datassist side by side on a single page.

Everything seems to be working ok, apart from the progress bar wich causes same ui error widely reported across this thread, however, that is not an issue for me at this time.

I have DFP creating dynamic folders and filenames based on the logged in users credentials, then the images are uploaded into the logged in users own folders, all fine.

However, my results page which loads after the record insert and image upload completes, is failing to display the images because the 'server directory' i'm saving to my sql table is capturing the whole root-path;

<img  src="<?php echo $row_WADApropmaintbl['propImgPath']; ?>/<?php echo $row_WADApropmaintbl['propImgFileName']; ?>" alt="<?php echo $row_WADApropmaintbl['propImgName']; ?>" name="" />

This translates into;

<img  src="/home/www/<?php echo $row_WADApropmaintbl['propImgFileName']; ?>" alt="<?php echo $row_WADApropmaintbl['propImgName']; ?>" name="" />

When all i need is the folder;

<img  src="/member_ref/<?php echo $row_WADApropmaintbl['propImgFileName']; ?>" alt="<?php echo $row_WADApropmaintbl['propImgName']; ?>" name="" />

Any ideas how i can replace the 'server directory' option with a folder name to apply in the Insert Record Wizard?

Thanks, Paul.

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Hi Paul,

My suggestion would be to simply save the File Name in the database.

Still let DFP create the folder dynamically, but then just keep the file name in the database.

Then, when you show the image, pull the dynamically created folder based on the recordset.

For example if you have a site member upload their photo, you might create a dynamic folder like "memberphotos_2" where "2" is the id number of the member in the database.

So then when showing the photo, it would look like this:

<img  src="memberphotos_<?php echo row_member['id']; ?>/<?php echo row_recordset2['image']; ?>" />

Best regards,


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PaulBeta Tester

Thanks Brian,
Just the nudge needed.
Problem resolved.


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