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Error Updating two different tables

Thread began 7/29/2010 8:00 pm by xarx1001412051 | Last modified 6/07/2012 2:49 pm by xarx1001412051 | 844 views | 3 replies


Updating two tables

Hi Jason,

Did this thread ever continue on? I have been looking for a solution for a similar situation where I can update an order or delete all or part of the order. When I create an update server behavious in DW how do i get it to recognize the two tables?

I have tried "join" and a few other things but with varying results.

This is what i have now but i get an error stating "Query Was empty"


$editFormAction = $_SERVER['PHP_SELF'];
if (isset($_SERVER['QUERY_STRING'])) {
$editFormAction .= "?" . htmlentities($_SERVER['QUERY_STRING']);

if ((isset($_POST["MM_update"])) && ($_POST["MM_update"] == "UpdateOrder")) {
$updateSQL = sprintf("UPDATE orders INNER JOIN orderdetails ON orders.OrderID = orderdetails.DetailOrderID SET orderdetails.DetailName=%s, orderdetails.DetailPrice=%s, orderdetails.DetailQuantity=%s, orders.OrderAmount=%s, orders.OrderShipName=%s, orders.OrderShipAddress=%s, orders.OrderShipAddress2=%s, orders.OrderCity=%s, orders.OrderState=%s, orders.OrderZip=%s, orders.OrderPhone=%s, orders.OrderEmail=%s WHERE orderdetails.DetailOrderID = %s AND orders.OrderID = %s",
// conected to order details table
GetSQLValueString($_POST['DetailName'], "text"),
GetSQLValueString($_POST['DetailPrice'], "int"),
GetSQLValueString($_POST['DetailQuantity'], "int"),
// contected to orders table
GetSQLValueString($_POST['OrderAmount'], "int"),
GetSQLValueString($_POST['OrderShipName'], "text"),
GetSQLValueString($_POST['OrderShipAddress'], "text"),
GetSQLValueString($_POST['OrderShipAddress2'], "text"),
GetSQLValueString($_POST['OrderCity'], "text"),
GetSQLValueString($_POST['OrderState'], "text"),
GetSQLValueString($_POST['OrderZIP'], "text"),
GetSQLValueString($_POST['OrderPhone'], "text"),
GetSQLValueString($_POST['OrderEmail'], "text"),
GetSQLValueString($_POST['OrderID'], "int"));

mysql_select_db($database_t0y0t1r3s, $t0y0t1r3s);
$Result1 = mysql_query($updateSQL, $t0y0t1r3s) or die(mysql_error());

I'll keep looking/working at it but if you have a quick fix ... thank you.

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